Free wave equation: Difference between revisions

From DispersiveWiki
Jump to navigationJump to search
(Added solution to the Cauchy problem for d=1+1)
m (Removed {{stub}} tag)
 
(10 intermediate revisions by the same user not shown)
Line 18: Line 18:
<center><math>\, f(x,t)=g_1(x-t)+g_2(x+t)\!</math></center>
<center><math>\, f(x,t)=g_1(x-t)+g_2(x+t)\!</math></center>


being <math>g_1,\ g_2</math> two arbitrary functions. This gives a complete solution to the Cauchy problem that can be cast as follows
being <math>g_1,\ g_2</math> two arbitrary functions and <math>\, x\in {\mathbb R}\!</math>. This gives a complete solution to the Cauchy problem that can be cast as follows


<center><math>\, f=f_0(x)\ \partial_tf=f_1(x)\!</math></center>
<center><math>\, f=f_0(x),\ \partial_tf=f_1(x)\!</math></center>


for <math>\, t=0\!</math>, so that
for <math>\, t=0\!</math>, so that
Line 28: Line 28:
being <math>\, F_1\!</math> an arbitrarily chosen primitive of <math>\, f_1\!</math>.
being <math>\, F_1\!</math> an arbitrarily chosen primitive of <math>\, f_1\!</math>.


{{stub}}
=== Solution in <math>{\mathbb R}^{1+d}</math> ===
 
Solution of the Cauchy problem in <math>{\mathbb R}^{1+d}</math> can be given as follows [[You1966]]. We have
 
<center><math>\, f=f_0(x),\ \partial_tf=0\!</math></center>
 
for <math>\, t=0\!</math>, but now <math>\, x\in {\mathbb R}^d\!</math>. One can write the solution as
 
<center><math>f(x,t)=\frac{t\sqrt{\pi}}{\Gamma(d/2)}\left(\frac{\partial}{\partial t^2}\right)^{(d-1)/2}[t^{d-2}\phi(x,t)]</math></center>
 
when d is odd and
 
<center><math>f(x,t)=\frac{2t}{\Gamma(d/2)}\left(\frac{\partial}{\partial t^2}\right)^{d/2}\int_0^t t_1^{d-2}\phi(x,t_1)\frac{t_1dt_1}{\sqrt{t^2-t_1^2}}</math></center>
 
when d is even, being
 
<center><math>\, \phi(x,t)=\frac{1}{\Omega_d}\int_{\Sigma(t)} f_0(x')d\Omega_d\!</math></center>
 
on the surface of the d-sphere centered at x and with radius t.
 
 
 
[[Category:Wave]]
[[Category:Wave]]
[[Category:Equations]]
[[Category:Equations]]

Latest revision as of 16:00, 1 July 2018

The free wave equation on is given by

where f is a scalar or vector field on Minkowski space . In coordinates, this becomes

It is the prototype for many nonlinear wave equations.

One can add a mass term to create the Klein-Gordon equation.

Exact solutions

Being this a linear equation one can always write down a solution using Fourier series or transform. These solutions represent superpositions of traveling waves.

Solution in

In this case one can write down the solution as

being two arbitrary functions and Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \, x\in {\mathbb R}\!} . This gives a complete solution to the Cauchy problem that can be cast as follows

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \, f=f_0(x),\ \partial_tf=f_1(x)\!}

for Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \, t=0\!} , so that

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle f(x,t)=\frac{1}{2}[f_0(x+t)+f_0(x-t)]+\frac{1}{2}[F_1(x+t)+F_1(x-t)]}

being Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \, F_1\!} an arbitrarily chosen primitive of Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \, f_1\!} .

Solution in Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle {\mathbb R}^{1+d}}

Solution of the Cauchy problem in Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle {\mathbb R}^{1+d}} can be given as follows You1966. We have

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \, f=f_0(x),\ \partial_tf=0\!}

for Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \, t=0\!} , but now Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \, x\in {\mathbb R}^d\!} . One can write the solution as

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle f(x,t)=\frac{t\sqrt{\pi}}{\Gamma(d/2)}\left(\frac{\partial}{\partial t^2}\right)^{(d-1)/2}[t^{d-2}\phi(x,t)]}

when d is odd and

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle f(x,t)=\frac{2t}{\Gamma(d/2)}\left(\frac{\partial}{\partial t^2}\right)^{d/2}\int_0^t t_1^{d-2}\phi(x,t_1)\frac{t_1dt_1}{\sqrt{t^2-t_1^2}}}

when d is even, being

Failed to parse (SVG (MathML can be enabled via browser plugin): Invalid response ("Math extension cannot connect to Restbase.") from server "https://en.wikipedia.org/api/rest_v1/":): {\displaystyle \, \phi(x,t)=\frac{1}{\Omega_d}\int_{\Sigma(t)} f_0(x')d\Omega_d\!}

on the surface of the d-sphere centered at x and with radius t.