Circle method: Difference between revisions
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(Created page with "$I_{k,\lambda} f(n)=\sum_{m=1}^\infty \frac{f(n-m^k)}{m^\lambda}$.") |
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Latest revision as of 19:27, 26 July 2011
$I_{k,\lambda} f(n)=\sum_{m=1}^\infty \frac{f(n-m^k)}{m^\lambda}$.
